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Question

The factorisation of 3a5−108a3 is equal to

A
3a3(a+6)(a+6)
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B
3a3(a6)(a+6)
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C
3a2(a6)(a6)
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D
3a3(a6)(a+6)
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Solution

The correct option is B 3a3(a6)(a+6)
The given expression is 3a5108a3
Taking out 3a3 we get

3a3(a236)
= 3a3(a262)
= 3a3(a6)(a+6)

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