Factorise $4 a^{2} + 4 a b + b^{2}$ .

(2 a - b)^{2}

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(4 a + b)^{2}

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(2 a + b)^{2}

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(a + 2 b)^{2}

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Solution

The correct option is C $(2 a + b)^{2}$
Given: $4 a^{2} + 4 a b + b^{2}$ .

Above expression can be written as, $(2 a)^{2} + 2 (2 a) b + b^{2}$

Using the identity $(a + b)^{2} = a^{2} + 2 a b + b^{2}$ we get, $4 a^{2} + 4 a b + b^{2} = (2 a + b)^{2}$ .

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