Question

Factorise $4a^2+4ab+b^2$ .

• A. $(2a-b{)}^2$
• B. $(4a+b{)}^2$
• C. $(a+2b{)}^2$
• D. $(2a+b{)}^2$

Answer 1

The correct option is D $(2a+b{)}^2$

Given: $4a^2+4ab+b^2$.

Above expression can be written as,$(2a{)}^2+2(2a)b+b^2$

Using the identity $(a+b{)}^2=a^2+2ab+b^2$ we get, $4a^2+4ab+b^2=(2a+b{)}^2$.