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Factorisation Using Algebraic Identities

Factorise: 4a...

Question

Factorise:

$4 a^{2} b - 9 b^{3}$

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Solution

$4 a^{2} b - 9 b^{3}$

= $b (4 a^{2} - 9 b^{2})$

= $b (2 a + 3 b) (2 a - 3 b)$

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Similar questions

Q. Factorize the equation

4 a^{2} b - 9 b^{3}

Factorise $4 a^{2} b - 12 a^{2} - 16 b + 48$

\frac{22 x}{4 a^{2} b} + \frac{11 x}{2 a b}

Q. Factor completely:

4 a^{2} b + 12 a b - 72 a b

Multiply:

$\frac{2}{3} a b$ by $- \frac{1}{4} a^{2} b$

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Factorisation Using Algebraic Identities

Standard VIII Mathematics

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