$F a c t o r i s e : 4 y^{2} - 12 y + 9$

$(7 y - 5) (7 y - 5)$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$(5 y - 3) (5 y - 3)$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$(2 y - 3) (2 y - 3)$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$(2 y - 5) (2 y - 5)$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
$(2 y - 3) (2 y - 3)$

The given expression can be rewritten as,
$(2 y)^{2} - 2 (2 y) (3) + 3^{2} .$
Comparing with the identity
$(a - b)^{2} = a^{2} - 2 a b + b^{2}$
we get,
$(2 y)^{2} - 2 (2 y) (3) + 3^{2}$
$= (2 y - 3)^{2}$
$= (2 y - 3) (2 y - 3)$

Suggest Corrections

Similar questions

Factorise : $x^{2} + 6 x + 9 - 4 y^{2}$

4 x^{2} + 4 y^{2} - 12 x - 12 y + 9 = 0

2 x^{2} + 11 x + 14 = 0

4 y^{2} + 12 y + 9 = 0

\frac{x^{2}}{4 y^{2}} - \frac{2}{3} + \frac{4 y^{2}}{9 x^{2}}

Factorise :

$(3 x - 4 y)^{2} - 25 z^{2}$

Join BYJU'S Learning Program