Factorise: $4 y^{2} - 4 y + 1$ .

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Solution

Given: $4 y^{2} - 4 y + 1$

$= 4 y^{2} - 2 y - 2 y + 1$

$= 2 y (2 y - 1) - 1 (2 y - 1)$
$= (2 y - 1) (2 y - 1)$

$= (2 y - 1)^{2}$

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