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Question

Factorise: 5a2−b2−4ab+7a−7b

A
(ab)(5+b+7)
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B
(ab)(5a+b+7)
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C
(a+b)(5a+b+7)
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D
(ab)(5+b7)
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Solution

The correct option is B (ab)(5a+b+7)
5a2b24ab+7a7b
=(a2b2)+(4a24ab)+(7a7b)
=(a+b)(ab)+4a(ab)+7(ab)
=(ab)(a+b+4a+7)
=(ab)(5a+b+7)

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