Factorise:
$6 x^{2} y^{3} - 12 x^{2} y^{2} + 18 x^{3} y$

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Solution

$6 x^{2} y (y^{2} - 2 y + 3 x)$
$= 6 x^{2} y (y (y - 2) + 3 x)$
This $x^{2}, y; (y^{2} - 2 y + 3 x)$ are its factors.

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Similar questions

4 x^{4} + 9 y^{4} + 6 x^{2} y^{2}

3 {(2 x - y)}^{3} + 9 {(2 x - y)}^{2}

A = 4 x^{2} + y^{2} - 6 x y, B = 3 y^{2} + 12 x^{2} + 8 x y

C = 6 x^{2} + y^{2} + 6 x y

A + B + C

- 2 x^{2} y^{3} + 6 x^{3} y^{2} - 8 x^{2} y^{2}

Factorise :

$12 x^{2} - 27$

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