If $A = 4 x^{2} + y^{2} - 6 x y, B = 3 y^{2} + 12 x^{2} + 8 x y$ and $C = 6 x^{2} + y^{2} + 6 x y$ , find $A + B + C$ .

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Solution

We have
$\begin{matrix} A = 4 x^{2} + y^{2} - 6 x y, B = 3 y^{2} + 12 x^{2} + 18 x y a n d C = 6 x^{2} + y^{2} + 6 x y N o w, A + B + C = 4 x^{2} + y^{2} - 6 x y + 3 y^{2} + 12 x^{2} + 18 x y + 6 x^{2} + y^{2} + 6 x y = 22 x^{2} + 5 y^{2} + 8 x y \end{matrix}$

Hence, $A + B + C = 22 x^{2} + 5 y^{2} + 8 x y$ .

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Similar questions

A = 4 x^{2} + y^{2} - 6 x y

B = 3 y^{2} + 12 x^{2} + 8 x y

C = 6 x^{2} + 8 y^{2} + 6 x y

A + B + C

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What should be subtracted from 2 x^{2} - 4 y^{2} + 6 x y + 10 to obtain - 2 x^{2} - 3 y^{2} + 6 x y + 10 ?

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