Factorise $6 a b - b^{2} - 2 b c + 12 a c$

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Solution

Given expression is $6 a b - b^{2} - 2 b c + 12 a c$
It can be factorised as,
$6 a b - b^{2} - 2 b c + 12 a c$
$= 6 a b - b^{2} + 12 a c - 2 b c$
$= b (6 a - b) + 2 c (6 a - b)$
$= (6 a - b) (b + 2 c)$

Thus factors are $(6 a - b)$ and $(b + 2 c)$ .

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