The quotient when $6 a b - b^{2} + 12 a c - 2 b c$ is divided by $(6 a - b)$ is ___

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Solution

The given expression is

$\frac{6 a b - b^{2} + 12 a c - 2 b c}{(6 a - b)}$

Consider the numerator,
$6 a b - b^{2} + 12 a c - 2 b c$

$= b (6 a - b) + 2 c (6 a - b)$

$= (b + 2 c) (6 a - b)$

Therefore,
$= \frac{6 a b - b^{2} + 12 a c - 2 b c}{(6 a - b)}$

$= \frac{(6 a - b) (b + 2 c)}{(6 a - b)}$

$= (b + 2 c)$

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Similar questions

(6 a b - b^{2} + 12 a c - 2 b c) d i v i d e d b y (6 a - b)

(6 a b - b^{2} + 12 a c - 2 b c) b y (6 a - b)

6 a b - b^{2} + 12 a c - 2 b c

\frac{6 a b - b^{2} + 12 a c - 2 b c}{b + 2 c}

Factorise :
$6 a b - b^{2} + 12 a c - 2 b c$

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