Factorise: $6 a x - 6 b y - 4 a y + 9 b x$

(3 x - 2 y) (2 a + 3 b)

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(x - 2 y) (a + 3 b)

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(3 x - y) (a + 3 b)

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(x - 2 y) (a - 3 b)

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Solution

The correct option is A $(3 x - 2 y) (2 a + 3 b)$
$6 a x - 6 b y - 4 a y + 9 b x$
$= 6 a x - 4 a y + 9 b x - 6 b y$
$= 2 a (3 x - 2 y) + 3 b (3 x - 2 y)$
$= (3 x - 2 y) (2 a + 3 b)$

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Similar questions

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f (x) =

∣ ∣ ∣ ∣ ∣ \begin{matrix} (1 + 3 x)^{2 a} & (1 + 2 x)^{3 b} & 1 1 & (1 + 3 x)^{2 a} & (1 + 2 x)^{3 b} (1 + 2 x)^{3 b} & 1 & (1 + 3 x)^{2 a} \end{matrix} ∣ ∣ ∣ ∣ ∣

Factorise by splitting the middle term: 24^{x 2}- 65^x+ 21

2 a + 6 b - 3 (a + 3 b)^{2}

2 a + 6 b - 3 (a + 3 b)^{2}

= 2 (a + 3 b) - 3 (a + 3 b)^{2} [T a k i n g 2 c o m m o n f r o m 2 a + 6 b]

= (a + 3 b) {\begin{matrix} 2 - 3 (a + 3 b) \end{matrix}} [T a k i n g (a + 3 b) c o m m o n]

= (a + 3 b) (2 - 3 a - 9 b)

x = \frac{\sqrt{a + 3 b} + \sqrt{a - 3 b}}{\sqrt{a + 3 b} - \sqrt{a - 3 b}}

3 b x^{2} - 2 a x + 3 b = 0

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