We will use identity a^2 b^2=(a b)(a+b) to factorise the given expression. 6x^2 54 amp;= 6( x^2 9) amp; = 6( x^2 3^2) amp; = 6( ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Factorisation Using Algebraic Identities

Factorise: ...

Question

Factorise: $6 x^{2} - 54$

Open in App

Solution

We will use identity $a^{2} - b^{2} = (a - b) (a + b)$ to factorise the given expression.

$\begin{matrix} 6 x^{2} - 54 & = 6 (x^{2} - 9) = 6 (x^{2} - 3^{2}) = 6 (x + 3) (x - 3) \end{matrix}$

Hence, factors are $6, x + 3$ and $x - 3.$

Suggest Corrections

Similar questions

6 x^{2} - 54

6 x^{2} + 7 x - 3

Factorise : $5 + 7 x - 6 x^{2}$

6 x^{2} - 11 x y - 10 y^{2}

Join BYJU'S Learning Program