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Question

Factorise: $$6x^2 - 54$$


Solution

We will use identity $$a^2-b^2=(a-b)(a+b)$$ to factorise the given expression.

$$\begin{aligned}{}6{x^2} - 54 &= 6\left( {{x^2} - 9} \right)\\& = 6\left( {{x^2} - {3^2}} \right)\\& = 6\left( {x + 3} \right)\left( {x - 3} \right)\end{aligned}$$

Hence, factors are $$6,\;x+3$$ and $$x-3.$$

Mathematics

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