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Question

Factorise:

(7) 49 + 28y + 4y2

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Solution

49 + 28y + 4y2
= (7)2 + 2 × 7 × 2y + (2y)2
= (7 + 2y)2 [a2 + 2ab + b2 = (a + b)2]
= (7 + 2y) (7 + 2y)
∴ 49 + 28y + 4y2 = (7 + 2y) (7 + 2y)

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