Factorise-7 x2-19 x-6

The #160;given #160;expression #160;is #160;7x2 19x 6.Find #160;two #160;numbers #160;that #160;follow #160;the #160;conditions #160;given ...

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Byju's Answer

Standard VIII

Mathematics

Factorisation by Common Factors

Factorise:7 x...

Question

Factorise:
7x² − 19x − 6

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Solution

$T h e g i v e n e x p r e s s i o n i s 7 x^{2} - 19 x - 6 . Find two numbers that follow the conditions given below : S u m = - 19 P r o d u c t = 7 \times - 6 = - 42 C l e a r l y, t h e n u m b e r s a r e - 21 a n d 2 . 7 x^{2} - 19 x - 6 = 7 x^{2} - 21 x + 2 x - 6 = 7 x (x - 3) + 2 (x - 3) = (7 x + 2) (x - 3)$

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Q. Solve

7 x^{2} - 19 x - 6 = ?

Q. Resolve each of the following quadratic trinomial into factor:
7x² − 19x − 6

Q. Factorise:
(i) x³ − 3x² + x − 3
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Using the remainder Theorem, factorise each of the following completely:
(i) $3 x^{3} + 2 x^{2} - 19 x + 6$
(ii) $2 x^{3} + x^{2} - 13 x + 6$
(iii) $3 x^{3} + 2 x^{2} - 23 x - 30$
(iv) $4 x^{3} + 7 x^{2} - 36 x - 63$
(v) $x^{3} + x^{2} - 4 x - 4.$

Q. Using the factor theorem factorise the following polynomial completely

3 x^{3} + 2 x^{2} - 19 x + 6

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Factorise: 7x2 − 19x − 6

The given expression is 7x2-19x-6.Find two numbers that follow the conditions given below: Sum =-19 Product =7×-6=-42Clearly, the numbers are -21 and 2.7x2-19x-6=7x2-21x+2x-6 = 7x(x-3)+2(x-3) =(7x+2) (x-3)

Factorise:
7x² − 19x − 6