Factorise :
$8 a^{2} + b^{3} + 12 a^{2} b + 6 a b^{2}$

(2 a - b) (2 a + b) (2 a + b)

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(2 a + b) (2 a - b) (2 a - b)

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(2 a + b) (2 a + b) (2 a + b)

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none of the above

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Solution

The correct option is C $(2 a + b) (2 a + b) (2 a + b)$
$8 a^{3} + b^{3} + 12 a^{2} b + 6 a b^{2}$
Using, $(a + b)^{3} = a^{3} + b^{3} + 3 a^{2} b + 3 a b^{2}$
$= (2 a)^{3} + (b)^{3} + (3 \times (2 a)^{2} b) + (3 \times (2 a) b^{2})$
$= (2 a + b)^{3}$
$= (2 a + b) (2 a + b) (2 a + b)$

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Similar questions

Factorise : 8a³ + b³ + 12a²b + 6ab²

8 a^{3} + b^{3} + 12 a^{2} b + 6 a b^{2}

= (2 a + b) (2 a + b) (2 a + b)

8 a^{3} - b^{3} - 12 a^{2} b + 6 a b^{2}

= (2 a - b) (2 a - b) (2 a - b)

(2 a + b) (2 a - b)

Factorise:
$a^{8} - 2 a^{4} b^{4} + b^{8}$

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