Factorise:

$8 a^{3} - b^{3} - 4 a x + 2 b x$

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Solution

$8 a^{3} - b^{3} - 4 a x + 2 b x = ({(2 a)}^{3} - b^{3}) - 2 x (2 a - b) = (2 a - b) ({(2 a)}^{2} + (2 a b) + b^{2}) - 2 x (2 a - b) = (2 a - b) (4 a^{2} + 2 a b + b^{2}) - 2 x (2 a - b) = (2 a - b) (4 a^{2} + 2 a b + b^{2} - 2 x)$

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Factorize $8 a^{3} - b^{3} - 4 a x + 2 b x$

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