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Question

Factorise 8a3b34ax+2bx

A
=(2ab)[4a2+b2+2ab2x]
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B
(2ab)[4a2+b+ab2x]
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C
(2ab)[4a2b22ab+2x]
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D
(2ab)[4a2+b2ab+2x]
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Solution

The correct option is A =(2ab)[4a2+b2+2ab2x]

8a3b34ax+2bx
=(2a)3b34ax+2bx
We know a3b3=(ab)(a2+ab+b2)
=(2ab)[4a2+b2+2ab]2x(2ab)
=(2ab)[4a2+b2+2ab2x]

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