The factors of 8a3 - b3 - 6ab -1 are- 2a - b - 1 4a2 - b2 - 4ab - 1 - 2a - b2a- b - 1 4a2 - b2 - 1 - 3ab - 2a 2a-1- b 4a2 - 1 - 4a- b - 2ab2a- b -1 4a2 - b2 - 1 - 2ab - b - 2a

The correct option is (2a)^3 + (b)^3 + (1)^3 3 × 2a × b × 1 = (2a+a b +1) [(2a)^2 + b^2 + 1 2a × b b × 1 1 × 2a] = (2a+a b + 1) (4a^2 + b^2 + 1 ...

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Algebraic Identities

The factors o...

Question

The factors of $8 a^{3} + b^{3} - 6 a b + 1$ are:

$(2 a + b - 1) (4 a^{2} + b^{2} + 1 - 3 a b - 2 a)$

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$(2 a - b + 1) (4 a^{2} + b^{2} - 4 a b + 1 - 2 a + b)$

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$(2 a + b + 1) (4 a^{2} + b^{2} + 1 - 2 a b - b - 2 a)$

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$(2 a - 1 + b) (4 a^{2} + 1 - 4 a - b - 2 a b)$

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