Factorise $9 x^{2} + 12 x y$ .

Open in App

Solution

We write $9 x^{2} + 12 x y = (3 x) (3 x) + (3 x) (4 y)$
Here $3 x$ is the common to both the terms. Hence
$(3 x) (3 x) + (3 x) (4 y) = 3 x (x + 4 y)$
Thus $3, x$ and $(3 x + 4 y)$ are the factors of $9 x^{2} + 12 x y$

Suggest Corrections

Similar questions

Factorise:
$9 x^{2} + 12 x y$

9 x^{2} + 4 y^{2} + 16 z^{2} - 12 x y - 16 y z + 24 x z

9 x^{2} + 4 y^{2} + 1 + 12 x y + 4 y + 6 x

9 x^{2} + 4 y^{2} + 16 z^{2} + 12 x y - 16 y z - 24 x z

9 x^{2} + 4 y^{2} + 16 z^{2} + 12 x y + 16 y z + 24 x z

Join BYJU'S Learning Program