Factorise 9 x 2-6 x -1-25 y

1) first make factor of =9x2+6x+1 identity 1 (a+b)2=a2+b2+2ab =(3x+1)2 25y2 =a2+b2=(a+b)(a b) =(3x+1)2 25y2 a=(3x+1) b=5y So the answer is (3x+1+5y)(3x+1 5y) ...

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Standard IX

Mathematics

Polynomials

Factorise 9 x...

Question

Factorise 9x²+6x+1-25y

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Solution

1) first make factor of

=9x²+6x+1 identity 1 (a+b)²=a²+b²+2ab

=(3x+1)²-25y² =a²+b²=(a+b)(a-b)

=(3x+1)²-25y² a=(3x+1) b=5y

So the answer is (3x+1+5y)(3x+1-5y)

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Factorise 9x²+6x+1-25y

1) first make factor of =9x2+6x+1 identity 1 (a+b)2=a2+b2+2ab =(3x+1)2-25y2 =a2+b2=(a+b)(a-b) =(3x+1)2-25y2 a=(3x+1) b=5y So the answer is (3x+1+5y)(3x+1-5y)

1) first make factor of

=9x²+6x+1 identity 1 (a+b)²=a²+b²+2ab

=(3x+1)²-25y² =a²+b²=(a+b)(a-b)

=(3x+1)²-25y² a=(3x+1) b=5y

So the answer is (3x+1+5y)(3x+1-5y)