Factorise:

$a^{2} + 4 b^{2} - 4 a b - 4 c^{2}$

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Solution

$a^{2} + 4 b^{2} - 4 a b - 4 c^{2} = (a)^{2} + (2 b)^{2} - 2 \times a \times 2 b - (2 c)^{2} = (a - 2 b)^{2} - (2 c)^{2} = (a - 2 b + 2 c) (a - 2 b - 2 c) {\begin{matrix} ∵ a^{2} - 2 a b + b^{2} = (a - b)^{2} (a + b) (a - b) = a^{2} - b^{2} \end{matrix}}$

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Similar questions

a^{2} + 4 b^{2} - 4 a b - 4 c^{2}

Factorise:
$a^{2} - b^{2} - 4 a c + 4 c^{2}$

Factorize :

(a + b + c)²- ( a- b - c)² + 4b²- 4c²

9 c - a^{2} + 4 a b - 4 b^{2}

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