Question

Factorise $a^2+7a+10$ + pa + 5p

• A. (a+5) + (a+ 2+ p)
• B. (a+5) + (a+ p)
• C. (a+2) + (a+ 5+ p)
• D. (a+7+ p) + (a+ p)

Answer 1

The correct option is A

(a+5) + (a+ 2+ p)

$a^2+7a+10+pa+5p$

$a^2+7a+10+pa+5p$
= $a^2+5a+2a+10+pa+5p$ ( Factorising $a^2+7a+10$)
= $a(a+5)+2(a+5)+pa+5p$
= $(a+2)(a+5)+pa+5p$
= $(a+2)(a+5)+p(a+5)$
= $(a+5)+(a+2+p)$