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Question

Factorise: a2(b+c)(b+c)3

A
(b+c)[(abc)(a+b+c)]
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B
(bc)[(abc)(ab+c)]
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C
(b+c)[(a+bc)(a+b+c)]
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D
(b+c)[(ab+c)(ab+c)]
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Solution

The correct option is A (b+c)[(abc)(a+b+c)]
a2(b+c)(b+c)3
=(b+c)[(a2(b+c)2]
[x2y2=(x+y)(xy)]
=(b+c)[(a(b+c))(a+(b+c))]
=(b+c)[(abc)(a+b+c)]

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