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Question

Factorise:

a2+b2-2ba+2bc-2ca

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Solution

a^2 + b^2 + 2bc - 2ca - 2ab =
(a^2 - 2ab + b^2) + 2bc - 2ca then
= (a - b)^2 - 2c(a - b) =
(a - b)[(a - b) - 2c)] =
(a - b)(a - b - 2c)

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