Factorise $a b^{2} - (a - c) b - c$

(b - 1) (a b + c)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(b - 1) (a b - c)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(b + 1) (a b - c)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(b + 1) (a b + c)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $(b + 1) (a b + c)$
$F a c t o r i z i n g {a b}^{2} - (a - c) b - c, = a b^{2} - a b + c b - c, = a b (b - 1) + c (b - 1) = (b - 1) (a b + c)$

Suggest Corrections

Similar questions

∣ ∣ ∣ ∣ \begin{matrix} 1 & a & b - a & 1 & c - b & - c & 1 \end{matrix} ∣ ∣ ∣ ∣ =

A = [\begin{matrix} 2 & 3 & 4 - 3 & 4 & 8 \end{matrix}],

B = [\begin{matrix} - 1 & 4 & 7 - 3 & - 2 & 5 \end{matrix}]

A + B = [\begin{matrix} 1 & a & b c & 2 & 13 \end{matrix}],

a + b + c .

a b > - 1, b c > - 1

c a > - 1

{cot}^{- 1} (\frac{a b + 1}{a - b}) + {cot}^{- 1} (\frac{b c + 1}{b - c}) + {cot}^{- 1} (\frac{c a + 1}{c - a})

\frac{1}{b c}, \frac{1}{c a}, \frac{1}{a b}

Join BYJU'S Learning Program