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Factorisation by Regrouping Terms

Factorise by ...

Question

Factorise by grouping method:

$a^{4} - 2 a^{3} - 4 a + 8$

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Solution

$a^{4} - 2 a^{3} - 4 a + 8 = a^{3} (a - 2) - 4 (a - 2) = (a - 2) (a^{3} - 4)$

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Similar questions

Factorize by the grouping method:

a^{4} - 2 a^{3} - 4 a + 8

Q. Factorize by grouping:

a^{4} - 2 a^{3} - 4 a + 8

Factorise:
$8 - 4 a - 2 a^{3} + a^{4}$

a^{4} - 2 a^{3} - 4 a + 8

by the grouping method

Q. The expression

a^{4} - 2 a^{3} - 4 a + 8

can be factorise as

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Factorisation by Regrouping Terms

Standard VIII Mathematics

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