Factorize by the grouping method:
$a^{4} - 2 a^{3} - 4 a + 8$

(a + 2) (a^{3} - 4)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(a + 4) (a^{3} - 2)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(a - 2) (a^{3} - 4)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(a - 2) (a^{3} + 4)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $(a - 2) (a^{3} - 4)$
$a^{4} - 2 a^{3} - 4 a + 8$
$= a^{4} - 4 a - 2 a^{3} + 8$
$= a (a^{3} - 4) - 2 (a^{3} - 4)$
$= (a^{3} - 4) (a - 2)$

Suggest Corrections

Similar questions

a^{4} - 2 a^{3} - 4 a + 8

a^{4} - 2 a^{3} - 4 a + 8

a^{4} - 2 a^{3} - 4 a + 8

Factorise by grouping method:

$a^{4} - 2 a^{3} - 4 a + 8$

Join BYJU'S Learning Program