Factorise by grouping method:

$m (x - 3 y)^{2} + n (3 y - x) + 5 x - 15 y$

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Solution

$m (x - 3 y)^{2} + n (3 y - x) + 5 x - 15 y$

= m (x - 3y)² - n (x - 3y) + 5(x - 3y)

=(x - 3y) [m(x - 3y) - n + 5] [Taking (x - 3y) common from all the three terms]

=(x - 3y)(mx - 3my - n + 5)

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Similar questions

m {(x - 3 y)}^{2} + n (3 y - x) + 5 x - 15 y

m (x - 3 y)^{2} + n (3 y - x) + 5 x - 15 y

Factorise by grouping method:

$x (6 x - 5 y) - 4 (6 x - 5 y)^{2}$

3 y^{2} = 15 y

15 y^{2} - 8 y + 1

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