Factorise: $16 a^{2} - 25 b^{2}$

(4 a - 5 b) (4 a - 5 b)

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(4 a - 5 b) (4 a + 5 b)

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(4 a + 5 b) (4 a + 5 b)

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(5 a - 4 b) (5 a + 4 b)

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Solution

The correct option is B $(4 a - 5 b) (4 a + 5 b)$
$16 a^{2} - 25 b^{2} = {(4 a)}^{2} - {(5 b)}^{2}$
$= (4 a - 5 b) (4 a + 5 b)$ .... $[∵ a^{2} - b^{2} = (a - b) (a + b)]$

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