Factorise: $36 x^{2} + 24 x + 4$

4 (3 x - 1) (3 x + 1)

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(3 x - 1) (3 x + 1)

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(3 x + 1) (3 x + 1)

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4 (3 x + 1) (3 x + 1)

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Solution

The correct option is D $4 (3 x + 1) (3 x + 1)$
$36 x^{2} + 24 x + 4$

$= {(6 x)}^{2} + 2 (2) (6 x) + {(2)}^{2}$

$= {(6 x + 2)}^{2}$ ... $[∵ {(a + b)}^{2} = a^{2} + 2 a b + b^{2}]$

$= 4 {(3 x + 1)}^{2}$

$= 4 (3 x + 1) (3 x + 1)$

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