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Question

Find the L.C.M. of 6x2x1, 3x2+7x+2 and 2x2+3x2


A

(x+2)(2x1)

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B

(2x1)(3x+1)

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C

(x+2)(2x1)(3x+1)

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D

(x+2)(2x+1)(3x+1)

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Solution

The correct option is C

(x+2)(2x1)(3x+1)


First expression = 6x2x1=6x23x+2x1=3x(2x1)+1(2x1)=(3x+1)(2x1)

Second expression = 3x2+7x+2=3x2+6x+x+2=3x(x+2)+1(x+2)=(3x+1)(x+2)


Third expression= 2x2+3x2=2x2+4xx2=2x(x+2)1(x+2)=(2x1)(x+2)


Required L.C.M. is (x+2)(2x1)(3x+1)


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