L.C.M. of $6 x^{2} - x - 1, 3 x^{2} + 7 x + 2 a n d 2 x^{2} + 3 x - 2$ is $(x + 2) (2 x - 1) (3 x + 1)$

True

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False

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Solution

The correct option is A
True

First expression = $6 x^{2} - x - 1 = 6 x^{2} - 3 x + 2 x - 1 = 3 x (2 x - 1) + 1 (2 x - 1) = (3 x + 1) (2 x - 1)$
Second expression = $3 x^{2} + 7 x + 2 = 3 x^{2} + 6 x + x + 2 = 3 x (x + 2) + 1 (x + 2) = (3 x + 1) (x + 2)$
Third expression= $2 x^{2} + 3 x - 2 = 2 x^{2} + 4 x - x - 2 = 2 x (x + 2) - 1 (x + 2) = (2 x - 1) (x + 2)$
Required L.C.M. is $(x + 2) (2 x - 1) (3 x + 1)$

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Similar questions

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