Factorise: $49 a^{2} - 64 b^{2}$

(7 a - 8 b) (7 a + 8 b)

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(7 a - 8 b) (7 a - 8 b)

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(7 a + 8 b) (7 a + 8 b)

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(7 a - 7 b) (8 a - 8 b)

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Solution

The correct option is A $(7 a - 8 b) (7 a + 8 b)$
$49 a^{2} - 64 b^{2} = {(7 a)}^{2} - {(8 b)}^{2}$
$= (7 a - 8 b) (7 a + 8 b)$ ... $[∵ a^{2} - b^{2} = (a - b) (a + b)]$

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