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Question

Factorise: 49a2−64b2

A
(7a8b)(7a+8b)
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B
(7a8b)(7a8b)
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C
(7a+8b)(7a+8b)
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D
(7a7b)(8a8b)
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Solution

The correct option is A (7a8b)(7a+8b)
49a264b2=(7a)2(8b)2
=(7a8b)(7a+8b) ...[a2b2=(ab)(a+b)]

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