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Question

Factorise :

8(3x2y)26x+4y1

A
(2x4y1)(2x8y+1)
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B
(6x4y1)(12x8y+1)
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C
(2x4y+1)(12xy+1)
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D
(6x4y+1)(x8y+1)
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Solution

The correct option is A (6x4y1)(12x8y+1)
8(3x2y)26x+4y1
=8(3x2y)22(3x2y)1
Let 3x2y=a
8a22a1
=8a24a+2a1
=4a(2a1)+1(2a1)
=(2a1)(4a+1)
Putting the value of a,
[2(3x2y)1][4(3x2y)+1]
=(6x4y1)(12x8y+1)

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