Factorise: $a + 2 b + a^{3} + 8 b^{3}$

(a + 2 b) (1 + a^{2} - 2 a b + 4 b^{2})

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(a - 2 b) (1 + a^{2} - 2 a b + 4 b^{2})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(a + 2 b) (1 - a^{2} - 2 a b + 4 b^{2})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(a + 2 b) (1 + a^{2} + 2 a b + 4 b^{2})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $(a + 2 b) (1 + a^{2} - 2 a b + 4 b^{2})$
$a + 2 b + a^{3} + 8 b^{3}$
$= (a + 2 b) + (a + 2 b) (a^{2} - 2 a b + 4 b^{2})$
$= (a + 2 b) (1 + a^{2} - a b + 4 b^{2})$

Suggest Corrections

Similar questions

$a^{2} + 2 a b + 4 b^{2}$ a perfect square trinomial

(a - b)^{2} = a^{2} - 2 a b + b^{2}

(5 a - 4 b)^{2}

Factorise $(a^{3} - 8 b^{3})$ .

Use the identity to compute:

(i) (x − 6)²; (ii) (3x − 5y)²; (iii) (5a − 4b)²; (iv) (p² − q²)².

Join BYJU'S Learning Program