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Algebraic Identities

Factorise:Fac...

Question

Factorise:

Factorization of $(x - 2 y)^{2} - 12 (x - 2 y) + 32$ is $(x - 2 y - 8) (x - 2 y - 4)$
If true then enter $1$ and if false then enter $0$

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Solution

Let $x - 2 y = a$
Factorizing $a^{2} - 12 a + 32$ ,
Split $12 a$ as:
$= a^{2} - 8 a - 4 a + 32 = a (a - 8) - 4 (a - 8) = (a - 8) (a - 4) = (x - 2 y - 8) (x - 2 y - 4)$

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