Question

Factorise :

$\frac{1}{35}+\frac{12}{35}a+a^2$

Answer 1

$\frac{1}{35}+\frac{12}{35}a+a^2=a^2++\frac{12}{35}a+\frac{1}{35}=a^2+\frac{1}{7}a+\frac{1}{5}a+\frac{1}{35}=a(a+\frac{1}{7})+\frac{1}{5}(a+\frac{1}{7})=(a+\frac{1}{7})(a+\frac{1}{5})$