Question

Factorise:
(i) 9x³ − 6x² + 12x
(ii) 8x³ − 72xy + 12x
(iii) 18a³b³ − 27a²b³ + 36a³b²

Answer 1

(i) H.C.F. of $9x^3$, $6x^2$ and $12x$ is $3x$.

∴ $9x^3-6x^2+12x=3x\left(3x^2-2x+4\right)$

(ii) H.C.F. of $8x^3$, $72xy$ and $12x$ is $4x$.

∴ $8x^3-72xy+12x=4x\left(2x^2-18y+3\right)$

(iii) H.C.F. of $18a^3{b}^3$, $27a^2{b}^3$ and $36a^3{b}^2$ is $9a^2{b}^2$.

∴ $18a^3{b}^3-27a^2{b}^3+36a^3{b}^2=9a^2{b}^2\left(2ab-3b+4a\right)$