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Byju's Answer
Standard IX
Mathematics
(x³±y³)
Factorise ∑...
Question
Factorise
∑
a
(
b
2
−
c
2
)
A
−
(
a
−
b
)
(
b
−
c
)
(
c
−
a
)
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B
(
a
−
b
)
(
b
−
c
)
(
c
−
a
)
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C
(
a
−
b
)
(
b
−
c
)
(
c
+
a
)
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D
None
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Solution
The correct option is
B
(
a
−
b
)
(
b
−
c
)
(
c
−
a
)
∑
a
(
b
2
−
c
2
)
=
a
(
b
2
−
c
2
)
+
b
(
c
2
−
a
2
)
+
c
(
a
2
−
b
2
)
⇒
a
b
2
−
a
c
2
+
(
b
c
2
−
b
a
2
)
+
c
a
2
−
c
b
2
⇒
(
a
−
c
)
b
2
+
a
c
(
a
−
c
)
+
[
b
(
c
−
a
)
(
c
−
a
)
]
⇒
(
a
−
c
)
(
b
2
+
a
c
−
b
c
−
a
b
)
=
(
a
−
c
)
[
b
(
b
−
c
)
−
a
(
b
−
c
)
=
(
a
−
b
)
(
b
−
c
)
(
c
−
a
)
]
Suggest Corrections
1
Similar questions
Q.
(
a
2
-
b
2
)
3
+
(
b
2
-
c
2
)
3
+
(
c
2
-
a
2
)
3
(
a
-
b
)
3
+
(
b
-
c
)
3
+
(
c
-
a
)
3
=
(a) 3(a + b) ( b+ c) (c + a)
(b) 3(a − b) (b − c) (c − a)
(c) (a − b) (b − c) (c − a)
(d) none of these