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Question

Factorise the expression: (a+3b)2−a2

A
2b(2a+3b)
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B
3b(3a+2b)
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C
3b(2a+3b)
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D
3b(2a-3b)
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Solution

The correct option is C 3b(2a+3b)
The given expression is (a+3b)2a2
= ((a+3b)a)((a+3b)+a) [Using the identity a2b2=(a+b)(ab)]

= (a+3b - a)(a+3b + a)
= 3b(2a+3b)

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