Factorise the expression: $(l m + l) + m + 1$

(l - 1) (m - 1)

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(l + 1) (m + 1)

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(l - 1) (m + 1)

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(l + 1) (m - 1)

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Solution

The correct option is A $(l + 1) (m + 1)$
$(l m + l) + m + 1$
$= l (m + 1) + 1 (m + 1)$
$= (m + 1) (l + 1)$

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