Factorise the expression using grouping method:
$18 a^{3} b^{2} + 36 a b^{4} - 24 a^{2} b^{3}$

6 a b^{2} (3 a^{2} + 6 b^{2} - 4 a b)

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6 a b^{2} (3 a^{2} - 6 b^{2} - 4 a b)

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6 a b^{2} (3 a^{2} + 6 b^{2} + 4 a b)

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6 a b^{2} (3 a^{2} - 6 b^{2} + 4 a b)

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Solution

The correct option is A $6 a b^{2} (3 a^{2} + 6 b^{2} - 4 a b)$
The highest common factor of the terms of the given expression is $6 a b^{2}$ . Hence we can write the expression as:
$18 a^{3} b^{2} + 36 a b^{4} - 24 a^{2} b^{3}$ = $6 a b^{2} (3 a^{2} + 6 b^{2} - 4 a b)$

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