Factorise the expression:
$(x^{2} + 3 x)^{2} - 5 (x^{2} + 3 x) - y (x^{2} + 3 x) + 5 y$

(x^{2} - 3 x - 5) (x^{2} + 3 x - y)

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(x^{2} - 3 x - 5) (x^{2} + 3 x - y)

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(x^{2} + 3 x - 5) (x^{2} + 3 x - y)

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(x^{2} + 3 x - 5) (x^{2} - 3 x - y)

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Solution

The correct option is C $(x^{2} + 3 x - 5) (x^{2} + 3 x - y)$
When we observe the given expression we find that $(x^{2} + 3 x)$ is a common factor between the first two terms and -y is acommon factor between the last two terms. Hence
$(x^{2} + 3 x)^{2} - 5 (x^{2} + 3 x) - y (x^{2} + 3 x) + 5 y$ = $(x^{2} + 3 x) [(x^{2} + 3 x) - 5] - y [(x^{2} + 3 x) - 5]$ = $(x^{2} + 3 x - 5) (x^{2} + 3 x - y)$

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Similar questions

(i) a^{3} x + a^{2} (x - y) - a (y + z) - z

(i i) (x^{2} + 3 x)^{2} - 5 (x^{2} + 3 x) - y (x^{2} + 3 x) + 5 y

a^{3} x + a^{2} (x - y) - a (y + z) - z

(x^{2} + 3 x)^{2} - 5 (x^{2} + 3 x) - y (x^{2} + 3 x) + 5 y

(x^{2} - 3 x)^{2} - 5 (x^{2} + 3 x) - y (x^{2} + 3 x) + 5 y

= (x^{2} + 3 x - 5) (x^{2} + 3 x - y)

5 x^{2} + 3 x - 14

Factorise:(3x- 5y)³+ (5y - 2z)³+ (2z - 3x)³

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