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Question

Factorise the following:
3a211ab+6b2

A
(a2b)(ab)
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B
(3a+b)(5ab)
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C
(a2b)(2a3b)
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D
(3a2b)(a3b)
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Solution

The correct option is D (3a2b)(a3b)
3a211ab+6b2
=3a29ab2ab+6b2
=3a(a3b)2b(a3b)
=(a3b)(3a2b)

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