Factorise the following trinomials:
$b^{2} + 4 b + 4$

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Solution

Solution:-
$b^{2} + 4 b + 4$
$= b^{2} + 2 b + 2 b + 4$
$= b (b + 2) + 2 (b + 2)$
$= (b + 2) (b + 2)$
Hence the factors of $b^{2} + 4 b + 4$ are $(b + 2)$ and $(b + 2)$ .

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