Question

Factorise the following using appropriate identities.
$3p^2-24p+36$

Answer 1

$3p^2-24p+36$ can be written as

$3\{p^2-(6+2)p+6\times 2\}$

We know appropriate identities $x^2-(a+b)x+ab=(x-a)(x-b)$

here $a=6andb=2$

$\therefore 3\{p^2-(6+2)+6\times 2\}$ = $3(p-6)(p-2)$