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Question

Factorise the given expression:
xypq+qypx


A

(py)(x+q)

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B

(yp)(x+q)

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C

(yp)(xq)

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D

(yx)(p+q)

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Solution

The correct option is B

(yp)(x+q)


Consider the given expression,

xypq+qypx...(i)

By suitably rearranging the terms in (i), we get

(xypx)+(qypq)...(ii)

Taking x common from first two terms and q common from last two terms, (ii) becomes

=x(yp)+q(yp)...(iii)

Taking (yp) common from (iii), we get

=(yp)(x+q)

xypq+qypx=(yp)(x+q)

Therefore, the factors of xypq+qypx are (yp) and (x+q).


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