Factorise:
$x^{2} + 6 a x + 9 a^{2}$

(x + 3)^{2}

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(x + 3 a)^{2}

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(x + a)^{2}

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(x - a)^{2}

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Solution

The correct option is B $(x + 3 a)^{2}$
$x^{2} + 6 a x + 9 a^{2}$
$= x^{2} + 2 \times x \times 3 a + (3 a)^{2}$
Using $a^{2} + b^{2} + 2 a b = (a + b)^{2}$
$= (x + 3 a)^{2}$

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Similar questions

9 a^{2} - 6 a x

Factorise:

$9 a^{2} - (a^{2} - 4)^{2}$

x : 9 x^{2} - 6 a x + (a^{2} - b^{2}) = 0.

y^{2} = 4 a x

45^{\circ}

\int \frac{d x}{\sqrt{x^{2} + a^{2}}} = l n | x + \sqrt{x^{2} + a^{2}} | + C

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\int \frac{d x}{a^{2} - x^{2}} = \frac{1}{2 a} l n ∣ ∣ \frac{x + a}{x - a} ∣ ∣ + C

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