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Question

Factorise:
x2+6ax+9a2

A
(x+3)2
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B
(x+3a)2
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C
(x+a)2
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D
(xa)2
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Solution

The correct option is B (x+3a)2
x2+6ax+9a2
=x2+2×x×3a+(3a)2
Using a2+b2+2ab=(a+b)2
=(x+3a)2

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